- Fri Jan 08, 2016 12:13 pm
#53885
DennisC - sorry, what? Resistance is load, more resistance is a bigger load, Ohm's Law. E=I/R. P=E^2/R. That tells us it takes more volts to shove the same current through a bigger resistance, a bigger weight to lift, more load. P=E*R. A low resistance will dissipate more power at same voltage; that's probably where our old brains are going in opposite directions, current and power. I did say resistive-load to avoid confusion with power because 'load' may also apply to the power dissipated.
The 23W bulbs have a lower resistance than 10W bulbs. The indicator bulb pairs are each wired in parallel, two on the left and two on the right. Wiring in parallel will halve the resistance (because they're the same), so if one blows open-circuit, the load is a single bulb.
I did use heavy handed back-of-beer-mat rounding, it gets nice round numbers
23W bulb = 23 = 12^2/R thus R = 144/23 = 6.260ohm = 6ohm
10W bulb, R = 144/10 = 14.4ohm = 14ohm, so two in parallel is 7ohm. That's about the same as one 23W bulb
23W bulbs in parallel is 3ohm but if one blows we have 6ohm and the flasher runs fast.